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271 lines (235 loc) · 7.06 KB
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package Novice_class;
public class BSExist {
// arr保证有序,在arr数组中寻找num,二分查找
public static boolean find(int[] arr, int num) {
if(arr == null || arr.length == 0) {
return false;
}
int L = 0;
int R = arr.length - 1;
while (L <= R) {
int mid = (L + R) / 2;
if(arr[mid] == num) {
return true;
}else if(arr[mid] < num) {
L = mid +1;
}else {
R = mid - 1;
}
}
return false;
}
// 有序数组中找到>=num最左的位置
// 1 2 2 3 4 5 6 7 数组
// 0 1 2 3 4 5 6 7 下标
// num == 2 return 1
public static int mostLeftNoLessNumIndex(int[] arr, int num) {
if(arr == null || arr.length == 1) {
return -1;
}
int L = 0;
int R = arr.length - 1;
// ans:是用来计数的,用来记录>=num的位置
int ans = -1;
while(L <= R) {
int mid = (L + R) / 2;
if(arr[mid] >= num) {
ans = mid;
R = mid - 1;
}else {
L = mid + 1;
}
}
return ans;
}
// 有序数组中找到<=num最右的位置
// 1 2 2 3 4 5 6 7 数组
// 0 1 2 3 4 5 6 7 下标
// num <= 2 return 2
public static int nearestIndex(int[] arr, int value) {
if(arr == null || arr.length == 1) {
return -1;
}
int L = 0;
int R = arr.length - 1;
// ans:是用来计数的,用来记录>=num的位置
int t = -1;
while(L <= R) {
int mid = (L + R) / 2;
if(arr[mid] <= value) {
t = mid;
L = mid + 1;
}else {
R = mid - 1;
}
}
return t;
}
// arr 相邻的数不相等! 返回一个局部最小的下标
public static int oneMinIndex(int[] arr) {
if(arr == null || arr.length == 0) {
return -1;
}
if(arr.length == 1) {
return 0;
}
int L = 0;
int R = arr.length - 1;
if(arr[L] < arr[L + 1]) {
return L;
}
if(arr[R] < arr[R - 1]) {
return R;
}
while(L <= R) {
int mid = (L + R) / 2;
if (arr[mid] < arr[mid + 1] && arr[mid] < arr[mid - 1]) {
return mid;
}
if(arr[mid] > arr[mid - 1]) {
R = mid - 1;
continue;
}
if(arr[mid] > arr[mid + 1]) {
L = mid + 1;
}
}
return -1;
}
// arr 相邻的数不相等! 返回一个局部最小的下标
public static int oneMinIndex2(int[] arr) {
if(arr == null || arr.length == 0) {
return -1;
}
if(arr.length == 1) {
return 0;
}
int L = 0;
int R = arr.length - 1;
if(arr[L] < arr[L + 1]) {
return L;
}
if(arr[R] < arr[R - 1]) {
return R;
}
while(L < R-1) {
int mid = (L + R) / 2;
if (arr[mid] < arr[mid + 1] && arr[mid] < arr[mid - 1]) {
return mid;
}
if(arr[mid] > arr[mid - 1]) {
R = mid - 1;
continue;
}
if(arr[mid] > arr[mid + 1]) {
L = mid + 1;
}
}
return arr[L] < arr[R] ? L : R;
}
// 生成随机数组,且相邻数不相等
public static int[] randomArray(int maxLen, int maxValue) {
int len = (int) (Math.random() * maxLen);
int[] arr = new int[len];
if (len > 0) {
arr[0] = (int) (Math.random() * maxValue);
for (int i = 1; i < len; i++) {
do {
arr[i] = (int) (Math.random() * maxValue);
} while (arr[i] == arr[i - 1]);
}
}
return arr;
}
// 也用于测试
public static boolean check(int[] arr, int minIndex) {
if (arr.length == 0) {
return minIndex == -1;
}
int left = minIndex - 1;
int right = minIndex + 1;
boolean leftBigger = left >= 0 ? arr[left] > arr[minIndex] : true;
boolean rightBigger = right < arr.length ? arr[right] > arr[minIndex] : true;
return leftBigger && rightBigger;
}
public static void printArray(int[] arr) {
for (int num : arr) {
System.out.print(num + " ");
}
System.out.println();
}
public static void main(String[] args) {
int maxLen = 100;
int maxValue = 200;
int testTime = 1000000;
System.out.println("测试开始");
for (int i = 0; i < testTime; i++) {
int[] arr = randomArray(maxLen, maxValue);
int ans = getLessIndex(arr);
if (!check(arr, ans)) {
printArray(arr);
System.out.println(ans);
break;
}
}
System.out.println("测试结束");
}
public static int oneMinIndex3(int[] arr) {
if (arr == null || arr.length == 0) {
return -1;
}
int N = arr.length;
if (N == 1) {
return 0;
}
//到这,arr的长度是大于等于2的
if (arr[0] < arr[1]) {
return 0;
}
if (arr[N - 1] < arr[N - 2]) {
return N - 1;
}
int L = 0;
int R = N - 1;
int ans = -1;
while (L <= R) {
int mid = (L + R) / 2;
//中间位置是否是最小,[mid-1] > [mid] < [mid+1]
if (arr[mid] < arr[mid - 1] && arr[mid] < arr[mid + 1]) {
ans = mid;
break;
//不同时小,下面两个判断选一个就行
} else if (arr[mid] > arr[mid - 1]) {
R = mid;
} else {//arr[mid] > arr[mid + 1]
L = mid;
}
}
return ans;
}
public static int getLessIndex(int[] arr) {
if (arr == null || arr.length == 0) {
return -1;
}
if (arr.length == 1 || arr[0] < arr[1]) {
return 0;
}
if (arr[arr.length - 1] < arr[arr.length - 2]) {
return arr.length - 1;
}
int left = 1;
int right = arr.length - 2;
int mid = 0;
while (left <= right) {
mid = (left + right) / 2;
if (arr[mid] > arr[mid - 1]) {
right = mid - 1;
} else if (arr[mid] > arr[mid + 1]) {
left = mid + 1;
} else {
return mid;
}
}
return -1;
}
}