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/*
Krishna Mohan
Project Euler - Problem 47
Date: 3/24/2015
*/
#include <bits/stdc++.h>
using namespace std;
#define fo(i, n) for(int (i)=0;(i)<(n); (i)++)
#define MAX 1000001
bitset<MAX> isPrime;
int primeCount[MAX];
vector<int> primes;
void init()
{
isPrime.set();
isPrime[0]=isPrime[1]=0;
for(int i=2;i<MAX;i+=2)
isPrime[i]=0;
primes.push_back(2);
for(int i=3;i<MAX;i+=2)
{
if(isPrime[i])
{
primes.push_back(i);
for(int j=2*i;j<MAX;j+=i)
isPrime[j]=0;
}
}
}
int main()
{
ios_base::sync_with_stdio(0);
init();
for(int i=3;i<MAX;i++)
{
if(isPrime[i])
primeCount[i]++;
else
{
int num=i, j=0;
//cout<<"i: "<<i<<endl;
while(num && primes[j]<num)
{
int f=0;
//cout<<"pj: "<<primes[j];
while(num%primes[j]==0 && num>0)
{
f=1;
num/=primes[j];
}
j++;
//cout<<" num: "<<num<<endl;
if(f==1)
primeCount[i]++;
if(isPrime[num])
{
primeCount[i]++;
break;
}
}
}
}
cout<<primeCount[644]<<" : "<<primeCount[645]<<" : "<<primeCount[646]<<endl;
int a=primeCount[0], b=primeCount[1], c=primeCount[2], d;
for(int i=2;i<MAX;i++)
{
c=primeCount[i];
if(a==3 && b==3 && c==3)
{
cout<<(i-2)<<" : "<<(i-1)<<" : "<<(i)<<endl;
break;
}
a=b;
b=c;
}
a=primeCount[0], b=primeCount[1], c=primeCount[2];
for(int i=3;i<MAX;i++)
{
d=primeCount[i];
if(a==4 && b==4 && c==4 && d==4)
{
cout<<(i-3)<<" : "<<(i-2)<<" : "<<(i-1)<<" : "<<(i)<<endl;
break;
}
a=b;
b=c;
c=d;
}
return 0;
}