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86 lines (66 loc) · 2.11 KB
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/*Heap sort is a comparison based sorting technique
* based on Binary Heap data structure. It is similar
* to selection sort where we first find the maximum
* element and place the maximum element at the end.
* We repeat the same process for remaining element.
*
* Time complexity of heapify is O(Logn).
* Time complexity of createAndBuildHeap() is O(n)
* and overall time complexity of Heap Sort is O(nLogn).
*/
package DataStructuresAndAlgorithms.src.sorts;
import java.util.Scanner;
public class HeapSort {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the no. of elements: ");
int n = sc.nextInt();
int[] intArray = new int[n];
System.out.println("Enter the elements:");
for (int i = 0; i < intArray.length; i++) {
intArray[i] = sc.nextInt();
}
heapSort(intArray);
System.out.println("The Sorted Array is:");
for (int i = 0; i < intArray.length; i++) {
System.out.println(intArray[i]);
}
sc.close();
}
public static void heapSort(int arr[]) {
int n = arr.length;
// Build heap (rearrange array)
for (int i = n / 2 - 1; i >= 0; i--)
heapify(arr, n, i);
// One by one extract an element from heap
for (int i = n - 1; i >= 0; i--) {
// Move current root to end
int temp = arr[0];
arr[0] = arr[i];
arr[i] = temp;
// call max heapify on the reduced heap
heapify(arr, i, 0);
}
}
// To heapify a subtree rooted with node i which is
// an index in arr[]. n is size of heap
public static void heapify(int arr[], int n, int i) {
int largest = i; // Initialize largest as root
int l = 2 * i + 1; // left = 2*i + 1
int r = 2 * i + 2; // right = 2*i + 2
// If left child is larger than root
if (l < n && arr[l] > arr[largest])
largest = l;
// If right child is larger than largest so far
if (r < n && arr[r] > arr[largest])
largest = r;
// If largest is not root
if (largest != i) {
int swap = arr[i];
arr[i] = arr[largest];
arr[largest] = swap;
// Recursively heapify the affected sub-tree
heapify(arr, n, largest);
}
}
}